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Ex 3.3
Ex 3.3, 1 Important
Ex 3.3, 2 Important
Ex 3.3, 3 Important
Ex 3.3, 4
Ex 3.3, 5 (i) Important
Ex 3.3, 5 (ii) You are here
Ex 3.3, 6 Important
Ex 3.3, 7
Ex 3.3, 8 Important
Ex 3.3, 9 Important
Ex 3.3, 10
Ex 3.3, 11 Important
Ex 3.3, 12
Ex 3.3, 13 Important
Ex 3.3, 14
Ex 3.3, 15
Ex 3.3, 16 Important
Ex 3.3, 17
Ex 3.3, 18 Important
Ex 3.3, 19
Ex 3.3, 20
Ex 3.3, 21 Important
Ex 3.3, 22 Important
Ex 3.3, 23 Important
Ex 3.3, 24
Ex 3.3, 25
Examples→
Chapter 3 Class 11 Trigonometric Functions
Serial order wise
- Ex 3.1
- Ex 3.2
-
Ex 3.3
- Examples
- Miscellaneous
- Principal and General Solutions
Last updated at April 16, 2024 by Teachoo
Transcript
Ex 3.3, 5Find the value of:(ii) tan 15°tan 15° = tan (45° – 30°)= (tan 45° − 〖 tan〗〖30°〗)/(1 + tan 45°tan〖30°〗 )= (1 − 1/√3)/(1 + 1 × 1/√3) = ((√3 − 1" " )/√3)/((√3 + 1" " )/√3) = (√3 −1)/√3 × √3/(√3 + 1) = (√𝟑 − 𝟏)/(√𝟑 + 𝟏)Rationalizing= (√3 − 1)/(√3 + 1) × (√3 − 1)/(√3 − 1)= (√3 − 1)2/(√3 + 1)(√3 − 1) Using (a – b)2 = a2 + b2 – 2ab= ((√3)2 + 12 − 2" " × √3 × 1)/(√3 + 1)(√3 − 1) = (3 + 1 − 2√3)/(√(3 )+ 1)(√3 − 1) Using (a – b ) (a + b) = a2 – b2= (𝟒 − 𝟐√𝟑)/((√𝟑)𝟐 − (𝟏)𝟐)= (4 − 2√3)/(3 − 1)= (2 (2 − √(3 )))/2= 2 – √𝟑Hence, tan 15° = 2 – √𝟑
Next: Ex 3.3, 6 Important → Go Ad-free
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Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.