Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (2024)

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Ex 3.3

Ex 3.3, 1 Important

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (2)

Ex 3.3, 2 Important

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (3)

Ex 3.3, 3 Important

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (4)

Ex 3.3, 4

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (5)

Ex 3.3, 5 (i) Important

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (6)

Ex 3.3, 5 (ii) You are here

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Ex 3.3, 6 Important

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Ex 3.3, 7

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (10)

Ex 3.3, 8 Important

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Ex 3.3, 9 Important

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Ex 3.3, 10

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Ex 3.3, 11 Important

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Ex 3.3, 12

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Ex 3.3, 13 Important

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Ex 3.3, 14

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Ex 3.3, 15

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Ex 3.3, 16 Important

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Ex 3.3, 17

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Ex 3.3, 18 Important

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Ex 3.3, 19

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Ex 3.3, 20

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Ex 3.3, 21 Important

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Ex 3.3, 22 Important

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Ex 3.3, 23 Important

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Ex 3.3, 24

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Ex 3.3, 25

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Examples→

Chapter 3 Class 11 Trigonometric Functions

Serial order wise

  • Ex 3.1
  • Ex 3.2
  • Ex 3.3

  • Examples
  • Miscellaneous
  • Principal and General Solutions

Last updated at April 16, 2024 by Teachoo

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (29)

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (30)

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (31)

Transcript

Ex 3.3, 5Find the value of:(ii) tan 15°tan 15° = tan (45° – 30°)= (tan 45° − 〖 tan〗⁡〖30°〗)/(1 + tan 45°tan⁡〖30°〗 )= (1 − 1/√3)/(1 + 1 × 1/√3) = ((√3 − 1" " )/√3)/((√3 + 1" " )/√3) = (√3 −1)/√3 × √3/(√3 + 1) = (√𝟑 − 𝟏)/(√𝟑 + 𝟏)Rationalizing= (√3 − 1)/(√3 + 1) × (√3 − 1)/(√3 − 1)= (√3 − 1)2/(√3 + 1)(√3 − 1) Using (a – b)2 = a2 + b2 – 2ab= ((√3)2 + 12 − 2" " × √3 × 1)/(√3 + 1)(√3 − 1) = (3 + 1 − 2√3)/(√(3 )+ 1)(√3 − 1) Using (a – b ) (a + b) = a2 – b2= (𝟒 − 𝟐√𝟑)/((√𝟑)𝟐 − (𝟏)𝟐)= (4 − 2√3)/(3 − 1)= (2 (2 − √(3 )))/2= 2 – √𝟑Hence, tan 15° = 2 – √𝟑

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Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (59)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Ex 3.3, 5 - Find the value of tan 15° [with Video] - Trigonometry (2024)

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